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# Area With the Cross Product - Problem 1

###### Norm Prokup

###### Norm Prokup

**Cornell University**

PhD. in Mathematics

Norm was 4th at the 2004 USA Weightlifting Nationals! He still trains and competes occasionally, despite his busy schedule.

Remember that, any two vectors will form or determine a parallelogram. Here I have an example; find the area of a parallelogram determined by vectors u equals <0 -1 2> and v equals <3 -1 0>. And I’ve drawn that parallelogram down here. This is v <3 -1 0> and this is u <0 -1 2>. Then I filled up the parallelogram that they determine. I want to find the area of that parallelogram.

So just remember, that we use the formula; area of the parallelogram equals the magnitude of u cross v. You remember that if you cross two vectors in the opposite or you get the opposite vector. But since we are taking the magnitude, we'll always get the right answer. So it actually doesn’t matter what order you cross these vectors in, because the magnitude will take care of that. But let’s go ahead and calculate this.

We’ve got i j k and I need the components of u first <0 -1 2> and then <3 -1 0>. So this is going to be i times the minor -1 2, -1 0, minus j times the minor 0 2, 3 0. Plus k times the minor 0 -1, 3 -1 and then I just calculate that. I have 0 minus -2, is plus 2i. 0 minus 6 times -1 is plus 6j, and this is 0 minus -3 plus 3, k.

The only problem here is I’ve calculated u cross v. This is u cross v, it’s not the magnitude of u cross v, maybe I should leave that off until later. So now I’ll do the area. The area is the magnitude of u cross v.

So the magnitude of this vector <2 6 3>. So that’s the square root of 2 square which is 4, plus 6 square root 36. Plus 3² which is 9, 13 plus 36 is 49. So that’s going to be 7 and that’s the area of our parallelogram. The area of this guy is 7.

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###### Norm Prokup

PhD. in Mathematics, University of Rhode Island

B.S. in Mechanical Engineering, Cornell University

He uses really creative examples for explaining tough concepts and illustrates them perfectly on the whiteboard. It's impossible to get lost during his lessons.

Thiswas EXCELLENT! I am a math teacher and have been looking for an easy/logical way to explain the lateral area of a cone to my students and this was incredibly helpful, thank you very much!”

I just learned more In 3 minutes of polygons here than I do in 3 weeks in my math class”

Hahaha, his examples are the same problems of my math HW!”

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