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Introduction to Logarithms  Problem 2
Carl Horowitz
Carl Horowitz
University of Michigan
Runs his own tutoring company
Carl taught upperlevel math in several schools and currently runs his own tutoring company. He bets that no one can beat his love for intensive outdoor activities!
Taking a equation from log form to exponential form. So for this equation we have a couple of equations up here and we're basically just changing them from forms, not changing the equation just moving from log form to the other.
So what we need to remember is our base will always remain the base, so in this case we're dealing with log base 3, the 3 is going to become the base of our exponential. The way I remember it is it comes up and under and then the log falls out. So basically the 3 changes signs everything else stays the same leaving us with 9 is equal to 3², the base comes up and under, everything else stays the same.
Same idea for this one down here 1/5 is our base, 1/5 is going to come up and under, 1/5 to 3 is equal to 125. I switched their signs down here but sides, but again equal signs you can flip things over, it doesn't really matter.
Taking things from exponential, sorry logarithm to exponential bases stay the same, it just gets switched over to the other side, everything else remains exactly where it is, just sort of being bumped up to an exponent.
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Carl Horowitz
B.S. in Mathematics University of Michigan
He knows how to make difficult math concepts easy for everyone to understand. He speaks at a steady pace and his stepbystep explanations are easy to follow.
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Introduction to Logarithms
Problem 1 9,875 viewsPut into logarithmic form.
25 = 5²3^{4} = 1 81 
Introduction to Logarithms
Problem 2 7,652 viewsPut into exponential form:
log_{3}9 = 2log_{⅕}125 = 3 
Introduction to Logarithms
Problem 3 1,501 views 
Introduction to Logarithms
Problem 4 1,417 views 
Introduction to Logarithms
Problem 5 1,317 views
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