##### Like what you saw?

##### Create FREE Account and:

- Watch all FREE content in 21 subjects(388 videos for 23 hours)
- FREE advice on how to get better grades at school from an expert
- FREE study tips and eBooks on various topics

# The Inverse Sine Function - Problem 3

###### Norm Prokup

###### Norm Prokup

**Cornell University**

PhD. in Mathematics

Norm was 4th at the 2004 USA Weightlifting Nationals! He still trains and competes occasionally, despite his busy schedule.

Let’s graph the transformation of the inverse sine function. The problem says graph y equals negative inverse sine of x plus pi over 2. Now let’s recall what the graph of inverse sine looks like.

This graph in blue is the graph of inverse sine and whenever I transform graphs I like to use key points and the key points I’m going to use are these three points, it's -1, negative pi over 2, 0, 0 and 1, pi over 2 and I’ve got those plotted out on this table. In order to graph my new function I need to think about what the transformations are going to do to these points.

When I look at this, I think reflection across the x axis and then shift down pi over 2. That means that only the y coordinates here are going to be affected. The reflection will change the sines like multiplying by -1 and then shifting up pi over 2 is like adding pi over 2. The x values will remain unchanged. -1, 0 and 1. And here I multiply by -1, I get pi over 2 plus pi over 2 gives me pi, times -1 plus pi over 2 is pi over 2. Times -1 plus pi over 2 is zero. So I get these three points which I can plot. -1, let me change colors here, negative one pi is up here. Zero, pi over 2 right here and 1 zero is right here. I want to try to mimic the shape of the inverse sine graph, so something like this.

This is the graph of y equals negative inverse sine of x plus pi over 2 and what’s really interesting about this graph is that it’s exactly the graph of y equals inverse cosine of x. that tells us that there’s an identity between these two and that is the inverse cosine of x equals negative inverse sine of x plus pi over 2. Which is kind of interesting. It means that if you want to evaluate and inverse cosine and your inverse cosine button’s broke on your calculator let’s say you calculate inverse sine times -1 plus pi over 2. That’s a transformation of the inverse sine graph.

Please enter your name.

Are you sure you want to delete this comment?

###### Norm Prokup

PhD. in Mathematics, University of Rhode Island

B.S. in Mechanical Engineering, Cornell University

He uses really creative examples for explaining tough concepts and illustrates them perfectly on the whiteboard. It's impossible to get lost during his lessons.

Thiswas EXCELLENT! I am a math teacher and have been looking for an easy/logical way to explain the lateral area of a cone to my students and this was incredibly helpful, thank you very much!”

I just learned more In 3 minutes of polygons here than I do in 3 weeks in my math class”

Hahaha, his examples are the same problems of my math HW!”

##### Concept (1)

##### Sample Problems (3)

Need help with a problem?

Watch expert teachers solve similar problems.

## Comments (0)

Please Sign in or Sign up to add your comment.

## ·

Delete