##### Like what you saw?

##### Create FREE Account and:

- Watch all FREE content in 21 subjects(388 videos for 23 hours)
- FREE advice on how to get better grades at school from an expert
- Attend and watch FREE live webinar on useful topics

# The Derivative Function - Problem 1

###### Norm Prokup

###### Norm Prokup

**Cornell University**

PhD. in Mathematics

Norm was 4th at the 2004 USA Weightlifting Nationals! He still trains and competes occasionally, despite his busy schedule.

By using the definition of the derivative, it is possible to find a formula for the derivative function. Recall that the definition of the derivative at some point x is the limit as h approaches 0 of (f(x+h)-f(x))/h. Substitute the x in f(x) with x+h and evaluate f(x) at this point. By plugging this value into the definition of the derivative and simplifying, you will find a new expression. When h approaches 0, the h's in this expression will become 0, so that the result is solely dependent on x.

We're talking about the derivative function. Here is a problem. Find the formula for the derivative function f'(x) where f(x) is x² plus 1. So the first thing we want to do is recall the definition of the derivative function. F'(x) is the limit as h approaches 0 of f(x+h) minus f(x) over h.

Now usually the first thing I do is I evaluate, and simplify the difference quotient. This inside part of the definition. So f(x) plus h minus f(x) over h for this function. Well, f(x+ h) is going to x plus h quantity squared plus 1. F(x) of course if just x² plus 1. All that over h.

So I have to expand all this, and simplify. There will be a little bit of cancellation. Now x plus h quantity squared is x² plus 2xh plus h², plus1 minus x² minus 12. Don't forget to distribute the minus sign. That's a mistake a lot of people make forgetting to distribute that.

Then you'll notice that a lot of simplification takes place. The x²s cancel, and the 1s cancel. You're left with 2xh plus 8² over h. You'll notice the common factor of h cancels, and you're left with 2x plus h. So you're difference quotients simplifies to 2x plus h.

Now we can pop this value back in for this guys. So we have the limit as h approaches 0 of 2x plus h. That's just 2x. That's our derivative function f'(x) is 2x. The linear function 2x. That's the derivative of f(x) equals x² plus 1.

Please enter your name.

Are you sure you want to delete this comment?

###### Norm Prokup

PhD. in Mathematics, University of Rhode Island

B.S. in Mechanical Engineering, Cornell University

He uses really creative examples for explaining tough concepts and illustrates them perfectly on the whiteboard. It's impossible to get lost during his lessons.

Thiswas EXCELLENT! I am a math teacher and have been looking for an easy/logical way to explain the lateral area of a cone to my students and this was incredibly helpful, thank you very much!”

I just learned more In 3 minutes of polygons here than I do in 3 weeks in my math class”

Hahaha, his examples are the same problems of my math HW!”

##### Concept (1)

##### Sample Problems (3)

Need help with a problem?

Watch expert teachers solve similar problems.

## Comments (0)

Please Sign in or Sign up to add your comment.

## ·

Delete