Learn math, science, English SAT & ACT from
highquaility study
videos by expert teachers
Thank you for watching the preview.
To unlock all 5,300 videos, start your free trial.
Dividing Radicals and Rationalizing the Denominator  Problem 2
Alissa Fong
Alissa Fong
MA, Stanford University
Teaching in the San Francisco Bay Area
Alissa is currently a teacher in the San Francisco Bay Area and Brightstorm users love her clear, concise explanations of tough concepts
This is a pretty ugly looking fraction because it has 2 square roots in the denominator. What I’m going to do to rationalize the denominator is multiply the top and bottom of this fraction by 1. It’s not just going to be the number 1 though, I’m going to multiply top and bottom by the conjugate of the denominator. Conjugate means it's going to have root 7 and root 10 still, only instead of a plus sign, it’s going to be a minus sign and here is why that’s clever.
Anytime you’re multiplying conjugates, you’re going to end up with an integer as your answer. Let me show you what I mean. Let’s look at the denominator and let’s FOIL. First, root 7 times root 7 is regular old 7. Outers, root 7 times root 10 is 70. Inners, I have + root 70 and then lasts I have 10, that was the Foiling on the bottom and then if you look those 2 terms cancel out, they’re additive inverses negative root 70 and positive root 70. So really on the bottom of my fraction I’m just going to have 7 take away 10 which is 3.
That was the whole point of this messy multiplication stuff by the way I’ll get back to the numerator in a second. All I wanted to show you here was the denominator. The reason why we multiplied by the conjugate is because instead of having these nasty square roots in the bottom, if we multiply by 1, we end up with 3 an integer in the denominator. That will always be the case if you multiply correctly by the conjugate.
Okay let’s go back to the top. Bottoms all done on top I needed to distribute this 4. So I’ll have 4 root 7 take away 4 root 10 and neither root 7 nor root 10 can be simplified any further, so I know that that’s my final answer.
So guys again if you see a product, excuse me, if you see a sum or difference of radicals in the bottom of a fraction, what you’re going to be doing is just multiplying by the conjugate of the denominator business. Make sure you change that sign. If it was a plus sign, you make it a minus sign here. After that it’s pretty straight forward, FOIL correctly, don’t lose any of your positive or negative signs and you guys will get the right answer.
Please enter your name.
Are you sure you want to delete this comment?
Alissa Fong
M.A. in Secondary Mathematics, Stanford University
B.S., Stanford University
Alissa has a quirky sense of humor and a relatable personality that make it easy for students to pay attention and understand the material. She has all the math tips and tricks students are looking for.
Sample Problems (10)
Need help with a problem?
Watch expert teachers solve similar problems.

Dividing Radicals and Rationalizing the Denominator
Problem 1 9,107 viewsSimplify:
5√8 √3x 
Dividing Radicals and Rationalizing the Denominator
Problem 2 7,310 viewsSimplify:
4 √7 + √10 
Dividing Radicals and Rationalizing the Denominator
Problem 3 7,026 viewsSimplify:
3 √12 + √8 
Dividing Radicals and Rationalizing the Denominator
Problem 4 859 views 
Dividing Radicals and Rationalizing the Denominator
Problem 5 787 views 
Dividing Radicals and Rationalizing the Denominator
Problem 6 822 views 
Dividing Radicals and Rationalizing the Denominator
Problem 7 681 views 
Dividing Radicals and Rationalizing the Denominator
Problem 8 714 views 
Dividing Radicals and Rationalizing the Denominator
Problem 9 832 views 
Dividing Radicals and Rationalizing the Denominator
Problem 10 762 views
Comments (0)
Please Sign in or Sign up to add your comment.
·
Delete