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Multiplying Polynomials: Special Cases  Problem 3
Alissa Fong
Alissa Fong
MA, Stanford University
Teaching in the San Francisco Bay Area
Alissa is currently a teacher in the San Francisco Bay Area and Brightstorm users love her clear, concise explanations of tough concepts
Here I have a product that we might not have seen before up to this point in your class. This one is different because not only is it x minus 2 to some exponent, but that exponent is 3. This is x minus 2 cubed, or to the third power. What that means is it’s the difference of x minus 2 times itself 3 times. Cubed means times itself times itself times itself that’s what it looks like.
So in order to do this problem, I’m going to do this step first and then whatever my answer is, I’m going to multiply it by x minus 2 at the end. Later on in your Math career, you’ll start seeing some short cuts for this maybe memorizing patterns, you don’t have to memorize patterns, you can always do this out by hand, but if you want to be a superstar and a Mathematician, you might want to look ahead in your text book or ask your teacher what the short cuts are here.
Let me show you the long way. So I’m going to go ahead and do this product first, then multiply by that. If I FOIL, my first will look like this, my outers, here come the inners and then plus 4, those are my lasts. When I go through and combine the middle term, it looks this. That’s just this first piece here. I still need to take that whole trinomial and multiply it by the x minus 2, because this represents x minus 2 squared, and then I need to multiply it by x minus 2 again in order to have x minus 2 to the third power.
Okay, so now I’m going to be doing that double distributing. I’m going to use some different colours to help myself stay organized. The first thing I need to do is take x and multiply it by each of these three terms. So x times x² is x to the third and minus 4x² plus 4x. That was all from distributing this x.
Now I’m going to go through and distribute the 2. Be really careful with the negative sign. 2x², +8x and then minus 8 at the end. To combine like terms, here comes my final answer. I’m going to have x to the third take away 6x², by the way this stays as x², it doesn’t become like x to the 0, or anything like that even though I’m subtracting it. Okay minus 6x² then I have plus 12 Xs take away. So there is my final answer for when I had to go through and take x minus 2 and multiply it by itself 3 times.
Again be really careful with your negative signs, make sure you go through it methodically and you should be getting the right answer on these homework problems.
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Alissa Fong
M.A. in Secondary Mathematics, Stanford University
B.S., Stanford University
Alissa has a quirky sense of humor and a relatable personality that make it easy for students to pay attention and understand the material. She has all the math tips and tricks students are looking for.
Your tutorials are good and you have a personality as well. I hope you have more advanced college level stuff, because I like the way you teach.”
Thanks alot for such great lectures... I never found learning this easier ever before... keep up the great work.... :)”
You seem so kind, it's awesome. Easier to learn from people who seem to be rooting for ya!' thanks”
Sample Problems (5)
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Multiplying Polynomials: Special Cases
Problem 1 5,181 viewsMultiply:
(3a + 2b)² 
Multiplying Polynomials: Special Cases
Problem 2 4,409 viewsMultiply:
(3a − 2b)(3a + 2b) 
Multiplying Polynomials: Special Cases
Problem 3 4,087 viewsMultiply:
(x − 2)³ 
Multiplying Polynomials: Special Cases
Problem 4 716 views 
Multiplying Polynomials: Special Cases
Problem 5 666 views
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