Like what you saw?
Create FREE Account and:
 Watch all FREE content in 21 subjects(388 videos for 23 hours)
 FREE advice on how to get better grades at school from an expert
 Attend and watch FREE live webinar on useful topics
Dividing Polynomials using Synthetic Division  Problem 1
Carl Horowitz
Carl Horowitz
University of Michigan
Runs his own tutoring company
Carl taught upperlevel math in several schools and currently runs his own tutoring company. He bets that no one can beat his love for intensive outdoor activities!
Using synthetic division to divide polynomials. So in order to, using that division to divide polynomials, we first have to look at our divisor, our denominator to make sure that if fits the restrictions that we need in order to use this process.
So the first restriction is that our denominator has to be of degree one, we can only have a single x, no x² and anything like that, so this one checks out. The second thing we have to look at is to make sure there is no coefficient on our X term, in this case we don’t, so we can use synthetic division.
How synthetic division works is we look at our denominator and pick the number that would make our denominator equal to zero, in this case 1. Once we have that written down, we make a little bracket and then in the same row that we wrote our 1, we want to write the coefficients for our dividend for our numerator, okay? We want to make sure that each power on x is accommodated for, so start with x³, add coefficient of 1.
Going down the line, we don’t have any x² terms, but we still need a place holder for it, so we need to put a 0 in there, continuing down to our x term, 13 and lastly 12. Okay, now, how synthetic division works, first we want to drop down this 1. Second we multiply the term on the outside by the term we just dropped down so 1 times 1 is 1, and then we add. So you have plus 1, 1. Continue this process all the way down the row, 1 times 1 becomes 1, add 12, 1 times 12 is 12 and our last term in this case is 0.
0 is the remainder so in this case we don’t have anything extra, and then interpreting your results is just going up by powers of X. So this first thing represents our constant term, this is going to be 12, from our constant term we go to our first degree term, this is –x, this turns into our x² which will be x².
We should always make sure because we’re dividing by a single x, your quotient, what you’re left with should always be one degree less than what you started with. So here we started with an x³, it makes sense that our quotient then is a x², okay? So using synthetic division to divide polynomials, going through the process, always make sure you put the number that gives you a 0 outside and then drop down your first term and then add.
Please enter your name.
Are you sure you want to delete this comment?
Carl Horowitz
B.S. in Mathematics University of Michigan
He knows how to make difficult math concepts easy for everyone to understand. He speaks at a steady pace and his stepbystep explanations are easy to follow.
i love you you are the best, ive spent 3 hours trying to understand probability and this is making sense now finally”
BRIGHTSTORM IS A REVOLUTION !!!”
because of you i ve got a 100/100 in my test thanks”
Sample Problems (5)
Need help with a problem?
Watch expert teachers solve similar problems.

Dividing Polynomials using Synthetic Division
Problem 1 5,788 viewsDivide:
x³ − 13x − 12 x + 1 
Dividing Polynomials using Synthetic Division
Problem 2 4,744 viewsDivide:
x³ + 2x − 4 2x − 1 
Dividing Polynomials using Synthetic Division
Problem 3 638 views 
Dividing Polynomials using Synthetic Division
Problem 4 581 views 
Dividing Polynomials using Synthetic Division
Problem 5 561 views
Comments (0)
Please Sign in or Sign up to add your comment.
·
Delete