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# Solving for a Parameter in a Linear Equation - Problem 1

###### Carl Horowitz

###### Carl Horowitz

**University of Michigan**

Runs his own tutoring company

Carl taught upper-level math in several schools and currently runs his own tutoring company. He bets that no one can beat his love for intensive outdoor activities!

Solving for a parameter. We’re trying to solve for x in this case, sorry, I didn’t write it up for you, and again remember, a, b and c are all numbers, so we’re going to treat them as we would, any other example. We’re actually solving for a number x. First, we want to get the term with x by itself, so subtract b over, c minus b, and then we have x over a. When you’re solving for x over something, we just multiply by that term.

If you think about x over 4 is equal to 3, we’re going to want to multiply by 4, multiply each side by 4 leaving us with x is 12. The same idea over here, except we’re doing it over a. So, multiply both sides by a and here our a's cancel, x is equal to, and remember here that we actually have to distribute that a through. Depending on your teacher, they might be okay with this form here, or they might prefer to see x is equal to ac minus ab, either one is correct but depending on your notation, different ways of expressing the same thing.

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###### Carl Horowitz

B.S. in Mathematics University of Michigan

He knows how to make difficult math concepts easy for everyone to understand. He speaks at a steady pace and his step-by-step explanations are easy to follow.

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