Like what you saw?
Create FREE Account and:
 Watch all FREE content in 21 subjects(388 videos for 23 hours)
 FREE advice on how to get better grades at school from an expert
 Attend and watch FREE live webinar on useful topics
Probability of Independent Events  Problem 2
Carl Horowitz
Carl Horowitz
University of Michigan
Runs his own tutoring company
Carl taught upperlevel math in several schools and currently runs his own tutoring company. He bets that no one can beat his love for intensive outdoor activities!
Finding the probability of independent events, and events that don't have any bearing on each other. So what we're looking at now is rolling a dice three times and if you think about it you roll a dice once, you pick it up you roll it again, the outcome from the first roll has no bearing on the outcome from the second, just like that similarly the second and first have no bearing on the third.
So the question we're looking at is the probability we roll just one odd number. So what we can look at that is we have the probability we roll an even and an even and an odd, we actually have three events that have to occur. They don't have any bearing on each other so really what we're looking for is probability of an even times probability of an even times probability of an odd.
So thinking about our die, there are six sides, 2, 4 and 6 occur once each so what we end up with is a three six a onehalf chance of rolling it even. That is the same thing for our second even and it's actually the same thing for our odd as well.
So what we have is onehalf times onehalf times onehalf, but what I did in this case is I've put my odd being my last roll sort of to assign it to a spot what we really have to do is take into account some sort of probability with this one and that is going to be where this odd can occur, we can get it first, we could get it second, we could get it third, so what we really have to do in this case is multiply this outcome by 3.
Another way you could do that is you want to us combinations, we could multiply this by 3 choose 1, we're rolling it three times, we're choosing where that odd is occuring but either way we took the probability of these three events, we multiplied them together.
In this particular case we have to consider order because a different outcome occurs when you have the odd first or third, so we need to multiply this by 3 and what we're going to end up with is threeeighths chance we roll just one odd.
Please enter your name.
Are you sure you want to delete this comment?
Carl Horowitz
B.S. in Mathematics University of Michigan
He knows how to make difficult math concepts easy for everyone to understand. He speaks at a steady pace and his stepbystep explanations are easy to follow.
i love you you are the best, ive spent 3 hours trying to understand probability and this is making sense now finally”
BRIGHTSTORM IS A REVOLUTION !!!”
because of you i ve got a 100/100 in my test thanks”
Get Peer Support on User Forum
Peer helping is a great way to learn. Join your peers to ask & answer questions and share ideas.
Concept (1)
Sample Problems (3)
Need help with a problem?
Watch expert teachers solve similar problems.

Probability of Independent Events
Problem 1 5,077 viewsMy brother was in a class of 20. I was in a class of 30.
Find the probability we were both valedictorians. 
Probability of Independent Events
Problem 2 4,689 viewsRoll a die three times.
Probability you roll just one odd number. 
Probability of Independent Events
Problem 3 4,206 viewsThe name of each student in your 30 student class is written on a slip of paper and put into a hat.
One slip is picked at random, put back into the hat, and then another slip is chosen.
Comments (0)
Please Sign in or Sign up to add your comment.
·
Delete